add: 将有序数组转换为二叉搜索树

README.md

@@ -511,6 +511,11 @@ LeetCode 与 LintCode 解题记录。此为个人练习仓库，代码中对重
   - LeetCode 105. 从前序与中序遍历序列构造二叉树 <https://leetcode-cn.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/>
   - LintCode 73. 前序遍历和中序遍历树构造二叉树 <https://www.lintcode.com/problem/construct-binary-tree-from-preorder-and-inorder-traversal/description>
 
+- [将有序数组转换为二叉搜索树](src/tree/convert-sorted-array-to-binary-search-tree.js)
+
+  - LeetCode 108. 将有序数组转换为二叉搜索树 <https://leetcode-cn.com/problems/convert-sorted-array-to-binary-search-tree/>
+  - LintCode 106. 有序链表转换为二叉搜索树 <https://www.lintcode.com/problem/convert-sorted-list-to-binary-search-tree/description>
+
 ## 链表
 
 - [合并 K 个排序链表](src/list/merge-k-sorted-lists.js)

src/tree/convert-sorted-array-to-binary-search-tree.js

@@ -0,0 +1,26 @@
+/**
+ * Definition for a binary tree node.
+ */
+function TreeNode(val) {
+  this.val = val
+  this.left = this.right = null
+}
+
+/**
+ * @param {number[]} nums
+ * @return {TreeNode}
+ */
+export const sortedArrayToBST = function (nums) {
+  if (!nums.length) return null
+
+  const creatTree = (left, right) => {
+    if (left > right) return null
+    const mid = Math.floor((left + right) / 2)
+    const root = new TreeNode(nums[mid])
+    root.left = creatTree(left, mid - 1)
+    root.right = creatTree(mid + 1, right)
+    return root
+  }
+
+  return creatTree(0, nums.length - 1)
+}

test/tree/convert-sorted-array-to-binary-search-tree.test.js

@@ -0,0 +1,5 @@
+import { sortedArrayToBST } from '../../src/tree/convert-sorted-array-to-binary-search-tree.js'
+
+test('将有序数组转换为二叉搜索树', () => {
+  expect(sortedArrayToBST()).toEqual()
+})