add: 最小覆盖子串
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.vscode/settings.json
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.vscode/settings.json
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@ -1,5 +1,6 @@
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{
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"cSpell.words": [
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"ADOBECODEBANC",
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"Gitpod",
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"LVIII",
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"Paddr",
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@ -104,6 +104,11 @@ LeetCode 与 LintCode 解题记录。此为个人练习仓库,代码中对重
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- LeetCode 1371. 每个元音包含偶数次的最长子字符串 <https://leetcode-cn.com/problems/find-the-longest-substring-containing-vowels-in-even-counts/>
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- [最小覆盖子串](src/string/minimum-window-substring.js)
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- LeetCode 76. 最小覆盖子串 <https://leetcode-cn.com/problems/minimum-window-substring/>
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-LintCode 1420. 最小覆盖子串II <https://www.lintcode.com/problem/minimum-window-substring-ii/description>
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## 数组/队列/集合/映射
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- [电话号码的字母组合](src/array/letter-combinations-of-a-phone-number.js)
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src/string/minimum-window-substring.js
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src/string/minimum-window-substring.js
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/**
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* @param {string} s
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* @param {string} t
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* @return {string}
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*/
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export const minWindow = function (s, t) {
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const sLen = s.length; const tLen = t.length
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const tMap = new Map(); const map = new Map()
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let l = 0; let r = 0; let res = ''
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for (let i = 0; i < tLen; i++) {
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tMap.set(t[i], (tMap.get(t[i]) || 0) + 1)
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}
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const check = (cMap) => {
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const check = new Map(
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[...cMap].filter(([k, v]) => tMap.has(k) && v >= tMap.get(k))
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)
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return check.size === tMap.size
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}
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while (r <= sLen) {
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if (t.includes(s[r])) {
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map.set(s[r], (map.get(s[r]) || 0) + 1)
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}
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while (check(map) && l <= r) {
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const tmp = s.slice(l, r + 1)
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if (res.length === 0 || tmp.length <= res.length) res = tmp
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if (t.includes(s[l]) && map.has(s[l])) {
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map.set(s[l], map.get(s[l]) - 1)
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}
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l++
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}
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r++
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}
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return res
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}
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test/string/minimum-window-substring.test.js
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test/string/minimum-window-substring.test.js
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import { minWindow } from '../../src/string/minimum-window-substring'
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test('最小覆盖子串', () => {
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expect(minWindow('ab', 'a')).toBe('a')
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expect(minWindow('ADOBECODEBANC', 'ABC')).toBe('BANC')
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expect(minWindow('a', 'a')).toBe('a')
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expect(minWindow('a', 'aa')).toBe('')
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expect(minWindow('abcdc', 'da')).toBe('abcd')
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})
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