add: 山脉数组中查找目标值

This commit is contained in:
yi-ge 2020-04-29 07:54:50 +08:00
parent 81d8dfae72
commit de9ff35202
3 changed files with 147 additions and 1 deletions

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@ -213,6 +213,12 @@ LeetCode 与 LintCode 解题记录。此为个人练习仓库,代码中对重
- LeetCode 136. 只出现一次的数字 https://leetcode-cn.com/problems/single-number/
- [山脉数组中查找目标值](src/array/find-in-mountain-array.js)
- LeetCode 1095. 山脉数组中查找目标值 https://leetcode-cn.com/problems/find-in-mountain-array/
- LeetCode 852. 山脉数组的峰顶索引 https://leetcode-cn.com/problems/peak-index-in-a-mountain-array/
- LintCode 585. 山脉序列中的最大值 https://www.lintcode.com/problem/maximum-number-in-mountain-sequence/description
## 栈
- [最大矩阵](src/stack/maximal-rectangle.js)
@ -260,4 +266,3 @@ LeetCode 与 LintCode 解题记录。此为个人练习仓库,代码中对重
- LeetCode 23. 合并K个排序链表 https://leetcode-cn.com/problems/merge-k-sorted-lists/
- LintCode 104. 合并k个排序链表 https://www.lintcode.com/problem/merge-k-sorted-lists/description

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@ -0,0 +1,111 @@
/**
* LeetCode 852. 山脉数组的峰顶索引
* @param {number[]} A
* @return {number}
*/
export const peakIndexInMountainArray = function (A) {
let left = 0
let right = A.length - 1
while (left < right) {
const mid = left + ((right - left) >> 1)
if (A[mid] > A[mid - 1] && A[mid] > A[mid + 1]) return mid
if (A[mid] < A[mid + 1] && A[mid] > A[mid - 1]) {
left = mid
} else {
right = mid
}
}
return 0
}
/**
* LintCode 585. 山脉序列中的最大值
* @param nums: a mountain sequence which increase firstly and then decrease
* @return: then mountain top
*/
export const mountainSequence = function (nums) {
let left = 0
let right = nums.length - 1
while (left < right) {
const mid = left + ((right - left) >> 1)
if (nums[mid] > nums[mid - 1] && nums[mid] > nums[mid + 1]) return nums[mid]
if (nums[mid] < nums[mid + 1] && nums[mid] > nums[mid - 1]) {
left = mid
} else {
right = mid
}
}
return nums[0]
}
/**
* // This is the MountainArray's API interface.
* // You should not implement it, or speculate about its implementation
* function MountainArray() {
* @param {number} index
* @return {number}
* this.get = function(index) {
* ...
* };
*
* @return {number}
* this.length = function() {
* ...
* };
* };
*/
/**
* 1095. 山脉数组中查找目标值
* @param {number} target
* @param {MountainArray} mountainArr
* @return {number}
*/
export const findInMountainArray = function (target, mountainArr) {
let left = 0
let right = mountainArr.length() - 1
// 山峰索引
let peak = 0
while (left < right) {
const mid = left + ((right - left) >> 1)
if (mountainArr.get(mid) > mountainArr.get(mid - 1) && mountainArr.get(mid) > mountainArr.get(mid + 1)) {
peak = mid
break
}
if (mountainArr.get(mid) < mountainArr.get(mid + 1) && mountainArr.get(mid) > mountainArr.get(mid - 1)) {
left = mid
} else {
right = mid
}
}
// 在山峰左边查找
const index = binarySearch(mountainArr, target, 0, peak, v => v)
// 若存在,则直接返回下标,否则在山峰右边查找
return index !== -1 ? index : binarySearch(mountainArr, target, peak + 1, mountainArr.length() - 1, v => -v)
// 二分法查找
// 其中 fn 是用来对升序还是降序的特殊处理
function binarySearch (mountainArr, target, l, r, fn) {
target = fn(target)
while (l <= r) {
const mid = (l + (r - l) / 2) | 0
const cur = fn(mountainArr.get(mid))
if (cur === target) {
return mid
} else if (cur < target) {
l = mid + 1
} else {
r = mid - 1
}
}
return -1
}
}

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@ -0,0 +1,30 @@
import { peakIndexInMountainArray, mountainSequence, findInMountainArray } from '../../src/array/find-in-mountain-array'
test('山脉数组的峰顶索引', () => {
expect(peakIndexInMountainArray([0, 1, 0])).toBe(1)
expect(peakIndexInMountainArray([0, 2, 1, 0])).toBe(1)
})
test('山脉序列中的最大值', () => {
expect(mountainSequence([1, 2, 4, 8, 6, 3])).toBe(8)
expect(mountainSequence([10, 9, 8, 7])).toBe(10)
})
function MountainArray (arr) {
this.arr = arr
// @param {number} index
// @return {number}
this.get = function (index) {
return this.arr[index]
}
// @return {number}
this.length = function () {
return this.arr.length
}
};
test('山脉数组中查找目标值', () => {
expect(findInMountainArray(3, new MountainArray([1, 2, 3, 4, 5, 3, 1]))).toBe(2)
expect(findInMountainArray(3, new MountainArray([0, 1, 2, 4, 2, 1]))).toBe(-1)
})