53 lines
1.0 KiB
JavaScript
53 lines
1.0 KiB
JavaScript
/**
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* 参考:https://leetcode-cn.com/problems/count-number-of-nice-subarrays/solution/count-number-of-nice-subarrays-by-ikaruga/
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* @param {number[]} nums
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* @param {number} k
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* @return {number}
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*/
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export const numberOfSubarrays = function (nums, k) {
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const odd = []
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odd.push(-1)
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let ans = 0
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let i = 1
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for (let j = 0; j <= nums.length; j++) {
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if (j === nums.length || (nums[j] & 1)) {
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odd.push(j)
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}
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if (odd.length - i > k) {
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const left = odd[i] - odd[i - 1]
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const right = j - odd[odd.length - 2]
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ans += left * right
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i++
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}
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}
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return ans
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}
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/**
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* 错误解法
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* @param {number[]} nums
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* @param {number} k
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* @return {number}
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*/
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// export const numberOfSubarrays = function (nums, k) {
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// let res = 0
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// for (let n = 0, len = nums.length; n < len; n++) {
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// let num = 0
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// let i = n
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// while (num < k && i < len) {
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// if (nums[i] % 2 !== 0) {
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// num++
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// }
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// i++
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// }
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// if (num === k) {
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// res++
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// }
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// }
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// return res
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// }
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